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Find the derivative y x ln x x2.

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Find the derivative y x ln x x2

   07.03.2020  10 Comments
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y = x ln x, Differentiate the function
Find the derivative y x ln x x2

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Find the derivative y x ln x x2
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Find the derivative y x ln x x2

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  • Answer: Rewrite as: y=eln(xlnx)=elnxlnx=e(lnx)2. Explanation: Now differentiate using the chain rule. dydx=e(lnx)2[2(lnx)(1x)]. =2lnxxxlnx.

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Find the derivative y x ln x x2

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  • DDX(LNY)=DDX(LNX(LNX)). 1Y(DYDX)=□. INSET: □. WE NEED TO DIFFERENTIATE LNX(LNX). BY THE PRODUCT RULE: [LNX(LNX)]'=1X×LNX+1X×LNX=LNXX+LNXX=2LNXX.
  • I WOULD USE THE PRODUCT RULE: Y'=2X⋅LN(X)+X2⋅1X=2XLN(X)+X=X[2LN(X)+1]. THE DERIVATIVE CALCULATOR...
  • FIND THE DERIVATIVE Y X LN X X2
  • FIND THE DERIVATIVE Y X LN X X2
  • DERIVATIVE OF Y = X X. A CALCULUS TUTORIAL ON HOW...

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  2. The Derivative Calculator lets you calculate derivatives of functions online — for free!

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